Question

in the given figure, Triangle BAC and CDB a right angle triangle at a and D respectively. a and D respectively if AC=BD,prove that ∆CAB=∆BDC​

Answer 1

Answer:

Step-by-step explanation:

Given, ∆ABC and ∆DCB are right angled at A and D.

AB = DC

To prove : ∆ ABC congruent ∆DBC

Proof

In ∆ABC and ∆DBC

AB = CD ( given )

BC = BC. ( Common)

Therefore, by RHS criteria

∆ABC congruent ∆DBC

By cpct Hence proved

Answer 2

Given, AC=BD

To prove: CAB=BDC

In CAB and BDC,

AC=BD (given)

angle BAC= angle BDC

BC= CB(same side)

So, they are congruent by RHS congruent property.