Question

In the given figure, triangle pqr is congruent to triangle psr bi RHS. the value of angle S is 10k° degree. find the value of k.​

Answer 1

Answer:

Angle Q = Angle S ( by CPCT )

We know that Angle Q =90

So, 90 = 10 K

10K = 90

K = 90/10

K = 9