In the given figure Triangle qps equal to triangle s r q find angle PSR
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since Triangle QPS= Triangle SRQ, and also since the quad PSQR is a parallelogram, the opp angle are equal and the sum of any two adjacent angle add up to 180°
i.e \_P=\_R
\_Q=\_S
and \_P +\_Q= 180°and so on for any two adjacent angle
so to find angle X we can use opp angle or adjacent angle formula
here iam usin opp angle which are equal in parallelogram
\_P=\_R
from fig \_P=106° and \_R= 2x +12
:. 106= 2x+12
106-12=2x
94/2=x
47=x
:. 47 is the value of X
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