In the given figure,two chords AB and CD of a circle intersect at O.If AO=8cm,CO=6cm and OD=4cm,then find the length of OB?
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Given:
AO=8cm, CO=6cm, and OD=4cm
To find:
The length of OB
Solution:
The required length of OB is 3 cm.
We can obtain the required length by equating the products of AO and OB and CO and OD.
Since AB and CD are the circle's chords and they meet at O, the product of the chords' segments will be equal.
AO×OB=CO×OD
Using the given values,
8×OB=6×4
8×OB=24
OB=24/8
OB=3 cm
Therefore, the required length of OB is 3 cm.
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