Math, asked by thunderboltblaster26, 7 months ago

in the given figure, two circles C1 and c2 touch each other internally at Q with centres O and O' respectively. If radii of bigger and smaller circles are 4 cm and 3 cm respectively and ACDB is the straight line of 2root15 cm, then find lengths of OA and AC​

Answers

Answered by amitnrw
2

Given :  two circles C1 and c2 touch each other internally at Q with centres O and O' respectively.  radii of bigger and smaller circles are 4 cm and 3 cm respectively and ACDB is the straight line of 2√15 cm

To Find : lengths of OA and AC

Solution:

AB = 2√15 cm

AB is chord of circle  C2

Radius of C2  = 4 cm   and center O'

O'A = O'B = 4cm

intersection of PQ  & AB  =  M

AM = BM = AB/2 = √15 cm

O'A² = O'M² + AM²

=> 4² = O'M² + (√15)²

=> 16 = O'M² +15

=> O'M² = 1

=> O'M =1

O'Q = 4 cm

OQ = 3cm

=> OO'  = 1 cm

O'M =1

=> OM = 1 + 1 = 2 cm

OA² = OM² + AM²

=> OA² = 2² + (√15)²

=> OA² = 4 + 15

=> OA = √19 cm

OC² = OM² + CM²

=> 3² = 2² + CM²

=>  CM² = 5

=> CM = √5  cm

AC​ = AM - CM  = √15 - √5

= √5(√3 - 1)  cm

OA = √19 cm

AC​ =  √5(√3 - 1)  cm

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