In the given figure, two concentric circles with centre O have radii 21 cm and 42 cm. If angle AOB = 60°, find the area of the shaded region.
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Area of inner circle: πr²
22/7 * 21 * 21
=1386 cm square
Area of outer circle= 22/7 * 42 * 42
=5544 cm square
Difference (area of outer circle- inner circle)= 5544-1386
=4158 cm square
We know that sum of angles around a point is 360 degrees
Since angle AOB is 60 degrees it is 1/6 of 360
Area of the shaded portion= 4158- 1/6 of 4158
=3465 cm square
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