In the given figure , two equal chords PQ and PR of a circle with center O, intersect at P.Show that OP bisect angle QPR.
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Answer:
given: PQ = PR; OQ = OR (radius of circle)
Here, in ∆POQ and ∆POR
- PQ = PR
- OQ = OR
- OP = OP (common)
therefore, ∆POQ = ∆POR
now, angle QPO = angle RPO
hence, OP bisect angle QPR
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0
Answer:
given answer
Step-by-step explanation:
- In the given figure , two equal chords PQ and PR of a circle with center O, intersect at P.Show that OP bisect angle QPR.
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