In the given figure two line segement AB and CD bisect each other at O . Prove that triangle AOD is congruent to triangle BOC
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Answer:if AD is ║ to BC then construct AC nad DB in a way that AC ll DB
therefor ADBC is a llgm
∠ AOD =∠ BOC(v ertically opposite angle )
CO= DO ( diagonals bisect )
AO =BO ( diagonals bisect)
thus by SAS ΔAOD≅ΔBOC
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