In the given figure, two line segments AD and AE of equal length length are drawn from the vertex A of triangle ABC such that BD=DE=CE.
what is the measure of angle EAC
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In quadrilateral ABCD we have AC = AD and AB being the bisector of ∠A. Now, in ΔABC and ΔABD, AC = AD[Given] AB = AB[Common]∠CAB = ∠DAB [∴ AB bisects ∠CAD] ∴ Using SAS criteria, we have ΔABC ≌ ΔABD. ∴ Corresponding parts of congruent triangles (c.p.c.t) are equal. ∴ BC = BD.
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