In the given figure, two lines pll q and r is transversal. if angle3= 135°, then find the remaining angles
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Answer:
∠2=∠6=∠4=∠7= 45° and ∠1=∠5=∠3=∠8=135°
Step-by-step explanation:
Given:
Line P ║ line q and r is transversal line. and ∠ 3 =135°
∠ 1 = ∠ 3 =135° ( vertically opposite angles are equal. as line p and line r intersect each other)
∠1 = ∠ 5= 135° (corresponding angles are equal.)
∠3 +∠6 =180° (sum of interior angle of one side is equal to 180° )
135° +∠6 =180°
∠ 6 = 180° -135°=45°
∠4 =∠6 =45° (alternate interior angles are equal)
∠2 =∠6=45° (corresponding angles are equal)
∠4 =∠7=45° (corresponding angles are equal)
∠2 +∠8 =180° (sum of exterior angle is 180°)
45° +∠8=180°
∠8 =180°-45°=135°
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4
Answer:
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