Question

In the given figure, two parallel lines and
are interested by two parallel lines and
Show that triangle ABC is congruent to triangleCDA​

Answer 1

the two parallel lines I and M are bisecting the pair of P and Q , by forming a vertical point or angle. We have to prove that the triangle ABC is similiar to CDA.

ABC=CDA

by taking the measurement of the angle of triangle ABC, we found that it's measure is(anything as suppose) 60°. Now we take the measurement of CBA= 60° itself.

so, ABC=60°, CBA=60°

=ABC=CBA as their measurement is clear to be the same

[proved]