in the given figure two straight line AB and CD intersect at point
o if angle aoc = 42 find the measure of each angle angle aod angle boc angle cob
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Answer:
dob=42
cob=88
aop=88
I thik so help it
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Answer:
42 × 2 + 2x = 360
84 + 2x = 360
2x = {360 - 84} 276
x = {276 ÷ 2} 138
* angle AOC. and POB Is 42°
* angle AOP and COB is 138°
check
42+ 42 + 138 + 138 = 360
84 + 276 = 360
360 = 360
LHS = RHS (proved)
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