In the given figure, two straight lines AB and CD intersect each other at O. If MOD = 86, then find the values of x, y and z
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★To find :
the angles x , y and z..
★ Solution :
angle AOB is a straight angle and thus , x ; 86° and 2x + 10 are linear pairs .
x + 86 + 2x + 10 = 180
3x + 96 = 180
3x = 180 - 96
3x = 84
x = 84/3
→ x = 28° .
angle AOD and angle COB are vertically opposite angles ..
Thus ,
x + 86 = y
28 + 86 = y
→ y = 114° ..
angle AOC and BOD are vertically opposite angles ..
thus ,
2x + 10 = 3z - 6
by putting value of x
2(28) + 10 = 3z - 6
56 + 10 = 3z - 6
66 = 3z - 6
3z = 66+6
3z = 72
z = 72/3
→ z = 24° ..
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