Question

In the given figure two straight lines AB and CD intersect at a point O.If AOC = 42° find the measure of each of the angles:
i. AOD , ii. BOD , iii. COB ​

Answer 1

${\Large{\bold{\rm{\red{Required \; Solution}}}}} \; \; \; \; \ddag$

AB and CD intersect at O and CD is a straight line.

(i) ∠COA+ ∠AOD = 180°   (linear pair)

42°+ ∠AOD  = 180°

∠AOD  = 138°_____answer

(ii) ∠COA and ∠BOD are vertically opposite angles. 

∴∠COA = ∠BOD = 42°   [from (i)]

(iii) ∠COB and ∠AOD are vertically opposite angles.

∴∠COB = ∠AOD = 138°  [from (i)]

Answer 2

Step-by-step explanation:

42+X =180

138

soo

AOD=138°

BOD=42°

COB=138°