Question

In the given figure: ( v ); prove that x = angle BAD + angle ABC + angle BCD

Answer 1

Construction :-

Join B to D and extend BD to E.

Now,

in ΔABD,

α + ∠ABD = ∠ADE    (i)   [ exterior angle ]

Similarly,

In ΔBCD,

∠DBC + $y$ = ∠CDE     (ii)

Add (i) and (ii)

⇒ ∠ADE + ∠CDE = (∠ABD + ∠DBC) + α + $y$

⇒ x = β + α + $y$

[ as ∠ADE + ∠CDE = x, ∠ABD + ∠DBC = β ]

Hence

Proved

Answer 2

Answer:

Hi bro, Sry for spamming the question but I have a doubt in one of your video plz check your comments section in deleting an account part 2

Step-by-step explanation: