In the given figure
Vector A+ VectorB +vector c is
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Let the given triangle be △ABC
Where, C'- B'= a' ( final vector - initial vector )
A'-C' = b'
A'-B'= c'
Now, we have to find a'+b'+c'
a'+b'+c' = C'- B'+A'-C'+A'-B'
= 2A'- 2B'
=2(A'-B')
= 2c'
Therefore the value of a'+b'+c'= 2c'
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