in the given figure xoy is a line find the value of angle xoz and angle zoy
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xoz + zoy = 180 (linear pair
2y+12+4y+18=180
6y+30=180
6y=180-30
6y= 150
y=150/6
y= 50/2=25
xoz = 2y+12
2×25+12=62°
zoy= 4y+18
4×25+18
100+18=118°
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Step-by-step explanation:
(2y+12)+(4y+18)= 180° (Linear Pair)
6y+30= 180°
6y= 180-30= 150
y= 150/6
So, 2y+12= 2(150/6)+12= 62°
4y+18= 4(150/6)+18= 118°
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