Question

In the given figure XY and PQ intersect at M, XP perpendicular PQ,YQ perpendicular and XP = YQ. Prove that triangle XPMc congruent triangle YQM​

Answer 1

Answer:

In △XQP and △XYZ,

∠XQP=∠XYZ=90

∘

∠QXP=∠YXZ (Common angle)

∴△XQP∼△XYZ

XZ

XP

=

XY

XQ

(By properties of similar triangle)

⇒

24cm

4cm

=

16cm

XQ

⇒XQ=

6

16

cm

⇒XQ=

3

8

cm

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