Question

in the given figure XY and X'Y' are two parallel tangents to a circle with centre O and another tangent AB with point of contact C, is intersecting XU at A and X 'Y' at B. prove that <AOB=90°​

Answer 1

Step-by-step explanation:

AOB=90°

Join OC

OC⊥AB

(Tangent at any point of circle is far to radius)

In ΔAOP & ΔAOC

OP=OC

AP=AC (length of drawn from external point to circle are equal).

Hence Proved ✓