In the given figure ΔXYZ and ΔPYZ are two isosceles triangle on the same base YZ with XY=XZ and PY=PZ. If ∠P=120 º and ∠XYP=40º, then find ∠YXZ. *

∠YXZ.=120º
∠YXZ.=90º
∠YXZ.=20º
∠YXZ.=40º
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Answer:
Your answer is 20.
Step-by-step explanation:
X+120+40=180.
X+160=180
X=180-160
X=20.
So, angle YXZ is 20.
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