In the given figure, ∆ XYZ, the two exterior angles are given. Find ∠ZXY.
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Answer:
/_ZXY=30°
Explanation:
● /_VYX + /_XYZ = 180°[Liner pair(L.P)]=180°-60°=120°
● /_XZU + /_XZY = 180°[L.P]=180-150=30°
● /_XYZ + /_XZY + /_XZY = 180°
120°+30°+/_XZY=180°
150°+/_XZY=180°
/_XYZ=180-150
/_XZY=30°
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