In the given figure, ZADE = ZB
(1) Show that AABC-AADE
(2) IfAD=3.8 cm, AE = 3.6cm,
BE = 2.1 cm and BC = 4.2 cm,
D
find DE
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Answer:
From given figure,
∠ADE=∠B
To prove: ΔADE∼ΔABC and
find DE
Given: AD=3.8cm, AE=3.6cm, BE=2.1cm and BC=4.2cm
Now, In ΔADE and ΔABC
∠ADE=∠B (given)
∠A=∠A (common)
ΔADE∼ΔABC (By AA)
Again,
AB
AD
=
BC
DE
AE+EB
AD
=
4.2
x
3.6+2.1
3.8
=
4.2
x
5.4
3.8
=
4.2
x
x=2.8
DE=2.8cm
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saipuni:
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