Question

In the given figure, ZADE = ZB
(1) Show that AABC-AADE
(2) IfAD=3.8 cm, AE = 3.6cm,
BE = 2.1 cm and BC = 4.2 cm,
D
find DE

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Answer 1

Answer:

From given figure,

∠ADE=∠B

To prove: ΔADE∼ΔABC and

find DE

Given: AD=3.8cm, AE=3.6cm, BE=2.1cm and BC=4.2cm

Now, In ΔADE and ΔABC

∠ADE=∠B (given)

∠A=∠A (common)

ΔADE∼ΔABC (By AA)

Again,

AB

AD

=

BC

DE

AE+EB

AD

=

4.2

x

3.6+2.1

3.8

=

4.2

x

5.4

3.8

=

4.2

x

x=2.8

DE=2.8cm

Answer 2

Refer The Attachment ⬆️

Hope It Helps You ✌️