Question

In the given figure, ZCAB. = ZCED, CD = 8 cm, CE = 10 cm, BE = 2
cm, AB = 9 cm, AD = b and DE = a, the value of a + b is
(A) 13 cm
(B) 15 cm
(C) 12 cm
(D) 9 cm​

Answer 1

$\huge\mathcal\pink{\boxed{\boxed{\boxed{Hlo\:Alpana}}}}$

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$\huge\mathcal\green{\boxed{Answer\:---}}$

Now in triangles ABC and EDC,

angle ACB = angle DCE

angle CAB = angle CED

So, by AA similarity, ABC similar to DEC,

We know,

Ration of sides of Similar triangle are same

So, AB/DE = BC/CE = AC/DC

9 / a = 12 / 10 = 8 + b / 10

So, 8+b / 10 = 12 / 10 ,,,, 9 / a = 12 / 10

8 + b = 12 ,,,,, 1 / a = 12 / ( 10 * 9 )

b = 12 - 8 ,,,,, 1 / a = 2 / 15

b = 4 ,,,, a = 15 / 2 = 7.5

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