Question

In the given figure, ZPSR = 90°, PQ = 10 cm,
QS = 6 cm and RQ = 9 cm, calculate the length
of PR.​

Answer 1

Answer:

By Pythagoras theorem,

In ∆ PQS,

PS= √(PQ^2-QS^2)=√(100-36)= √64=8cm

Now,

In ∆PRS,

PS=8cm

RS= RQ+QS=9cm+6cm=15cm

So,

By Pythagoras theorem,

PR=√(PS^2+RS^2)=√64+225=√289= 17cm

.......!

Answer 2

Answer:

The the length  of PR = 17 cm.

Step-by-step explanation:

This problem can be solve using Pythagoras Theorem.

This theorem is used for Right angle triangle. In right angle triangle if one of the side is unknown then we can find it by using formula:

(Hypotenuse)² = (Base)² + (Perpendicular)²

Firstly take the ΔPQR, We have

PQ = 10, QS = 6 and PS = ?

⇒ (PQ)² = (QS)² + (PS)²

⇒ 100 = 36 + (PS)²

⇒ (PS)² = 100 - 36 = 64

⇒ PS = 8

Now, taking the triangle PRS

We have, PS = 8, RS = RQ + QS = 9 + 6 = 15, and PR = ?

Using Pythagoras Theorem. We have,

(PR)² = (RS)² + (PS)²

⇒ (PR)² = 225 + 64

⇒ (PR)² = 289

⇒ PR = 17

Thus, The the length  of PR = 17 cm.