Question

In the given figures...​

Answer 1

Answer:

110⁰+PQR = 180⁰ (linear pair)

PQR = 180⁰-110⁰

PQR = 70⁰

135⁰ = 70⁰ + PRQ

PQR = 135⁰-70⁰

PQR = 65⁰

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Answer 2

Given :

• ∠SPR = 135°
• ∠PQT = 110°

To Find :

• ∠PRQ

Solution :

$\longmapsto\tt{\angle{PQT}+\angle{PQR}=180\degree}$

$\longmapsto\tt{110\degree+\angle{PQR}=180\degree}$

$\longmapsto\tt{\angle{PQR}=180\degree-110\degree}$

$\longmapsto\tt\bf{\angle{PQR}=70\degree}$

Now ,

$\longmapsto\tt{\angle{SPR}=\angle{PQR}+\angle{PRQ}}$

$\longmapsto\tt{135\degree=70\degree+\angle{PRQ}}$

$\longmapsto\tt{135\degree-70\degree=\angle{PRQ}}$

$\longmapsto\tt\bf{\angle{PRQ}=65\degree}$