Question

in the given figures, AOC is a straight line. find the measure of < AOB and < BOC.

please solve it is urgent​

Answer 1

Answer:

Answer is 26

Step-by-step explanation:

As it is a straight line, the sum of angles will be 180

Then,

(3x + 20) + (2x + 30) = 180

5x + 50 = 180

x = 130/5

x = 26

Answer 2

Solution :-

$\sf \: AOC \: is \: a \: straight \: line.$

Sum of angles on straight line = 180°

$\sf \angle \: AOB \: + \angle \: BOC \: = \: 180 \degree$

$\sf \: 3x + 20 \degree + 2x + 30 \degree \: = \: 180 \degree \\ \sf \: 5x + 50 \degree \: = \: 180 \degree \\ \sf \: 5x \: = \: 180 \degree \: - 50 \degree \\ \sf \: 5x \: = \: 130 \degree \\ \sf \: x \: = \: \frac{ \cancel{130} \: ^{26} \degree}{ \cancel5} \: \: \: \: \: \\ \boxed{\sf \: x = 26 \degree} \\ \\ \sf \: \angle \: AOB \: = 3x + 20 \degree \\ \sf \: = \: 3 \times 26 \degree \: + 20 \degree \\ \boxed{ \red{ \sf \: = \: 98 \degree}} \\ \\ \sf \angle \: BOC \: = \: 2x + 30 \degree \\ \sf \: = \: 2 \times 26 \degree \: + 30 \degree \\ \boxed{ \red{\sf \: = \: 82 \degree}}$