Question

in the given figures. find the measure of each of the following angles:
i. <AOD
ii. <DOB
iii.<BOC
iv. <AOC

please solve it is urgent please

with process​

Answer 1

Answer:

3x+20+2x-5=180

5x=180-15

x=165/5

x=33

<AOD= 119

<DOB=61

4x+x-5=180

5x=180+5

x=185/5

x=37

<BOC=148

<AOC=32

Hope it will help you

Answer 2

Answer:

Question :

In the given figures. find the measure of each of the following angles:

i. <AOD

ii. <DOB

iii.<BOC

iv. <AOC

Answer :

Sum of all angles in a point is 360°.

3x+20°+(2x-5°)+(x-5°)+4x° = 360°

10x + 10° = 360°

10x = 360° - 10°

10x = 350°

x = 350°÷10

x= 35°

Now, we found x value.

x=35°

Step-by-step explanation:

find the measure of each of the following angles:

i. <AOD = 3x+20°

= 3×35+20°

= 105°+20°

= 125°

ii. <DOB = 2x-5

= 2 × 35 -5°

= 70° -5°

= 65°

iii.<BOC = x-5°

= 35° - 5 °

= 30°

iv. <AOC = 4x

= 4 × 35°

= 140°

Therefore, hence found.

In the given figures,the measure of each of the following angles:

i. <AOD = 125°

ii. <DOB = 65°

iii.<BOC = 30°

iv. <AOC = 140°