In the given figures, find the values of x and y
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1 . x + 40° + 95° = 180° ( angle sum property )
x + 135° = 180°
x = 180° - 135 °
x = 45°
y + 110° + 45° = 180° ( angle sum property )
y + 155° = 180°
y = 180° - 155°
y = 25°
2. x = 35° + 40° ( exterior angle property of a triangle )
x = 75°
y = 75° + 38° ( exterior angle property of a triangle )
y = 113°
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Answer:
i)Δfbc=180°
40+95+x=180
135+x=180
x=45
in triangle Δabd
x+110+y=180
x=45
110+45+y=180
=155+y=180
y=25
ii)in triangle abc
35+40+t=180
t=180-75
t=105
x+t=180(angle sum property)
x+105=180
x=180-105
x=75
x+38+y=180
x=75
75+38+d=180
d=67
d+y=180(angle sum property)
d=67
y=180-67=113
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