Question

In the given figures, find the values of x and y.
With complete steps​

Answer 1

Step-by-step explanation:

(i)

70°+x=130°

x=130°-70°

x=60°

x+y+70°=180°

60°+y+70°=180°

Y+110°=180°

y=180°-110°

y=70°

(ii)

y+50°+85°=180°

y+135°=180°

y=180°-135°

y=45°

50+(y+40)+x=180

50+(45+40)+x=180

50+85+x=180

135+x=180

x=180-135

x=45

(iii)

x+30=70

x=70-30

x=40

x+y+30=180

40+y+30=180

y+70=180

y=180-70

y=110

Answer 2

QUESTION::

FIND THE VALUES OF X AND Y IN GIVEN FIGURES...

SOLUTION:

i) Given IN TRIANGLE ABC

<CAB = 70°

<ABC= x

<ACB= y

and < DCB = 130°

We know , 130° = 70° + <x

or, x = 130° - 70°

or , x = 60°

As we know the sum of interior angles of a triangle is 180°

we can say that 70° + 60° + y = 180°

therefore y = 180 - (70+60) = 180 - 130 = 50°

ii) Given triangle ∆ABC in which line segment CD divides the ∆ABC into two parts ∆ ABD and ∆ ACD

In triangle ACD

50°+85°+y = 180°

or, y = 180° -(50+85)

or, y = 180 - 135

or, y = 45°

In triangle BCD

< CDB = 180- 85 = 95° ( linear pair)

x = 180° - (40°+95°)

x = 180° - 135

x = 45°

iii) In the third triangle .

Angle y = 180° - 70° = 110° ( linear pair)

and x = 180°- ( 110° + 30°)

or, x = 180° - 140°

or x = 40°

CONCLUSION:

(i) x= 60°

y= 50°

(ii) x= 45°

y = 45°

(iii) x = 40°

y = 110°

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