in the given figures , <AOB=120⁰ and <DOC=110⁰. find the measure of the each of the following angles:
i. <AOC
ii.<AOB
iii.<AOD
please solve it is urgent please
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kiranpreet9:
120-50=2x
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Answer:
∠AOB =120°
⇒ ∠AOC + ∠BOC = 120
⇒ ∠AOC = 120-50
⇒ ∠AOC = 70°
⇒ 2x = 70°
∠AOB = 120° (given )
∠BOD = ∠DOC - ∠BOC
⇒ 3y = 110 - 50
3y = 60°
∴∠AOD = 360 - (60 + 50 + 70)
⇒ ∠AOD = 360 - 180
⇒ ∠AOD = 180°
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