In the given figures parts of triangles bearing identical marks are congruent. State the test and the one to one correspondence of vertices by which the triangles in each pair are congruent.
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Answered by
7
hey mate here's ur ans ↓↓
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⑴ It is congruent by the condition S.S.S.
⑵ It is congruent by the condition A.S.A.
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hope it helps u ☺☺✌
※※※※※※※※※※※※※※※※
⑴ It is congruent by the condition S.S.S.
⑵ It is congruent by the condition A.S.A.
※※※※※※※※※※※※※※※※
hope it helps u ☺☺✌
Answered by
5
Solution :
1 ) From the figure ( i ),
In ∆PQR and ∆UTS
PQ = UT ( S )
PR = US ( S )
QR = TS ( S )
Therefore,
∆PQR is congruent to ∆UTS
[ SSS criterion ]
2 ) From figure ( ii ) ,
In ∆ABD and ∆CBD
<ADB = <CDB ( A )
DB = BD ( common side )
<ABD = <CBD ( A )
Therefore ,
∆ABD is congruent to ∆CBD
[ ASA criterion ]
••••
1 ) From the figure ( i ),
In ∆PQR and ∆UTS
PQ = UT ( S )
PR = US ( S )
QR = TS ( S )
Therefore,
∆PQR is congruent to ∆UTS
[ SSS criterion ]
2 ) From figure ( ii ) ,
In ∆ABD and ∆CBD
<ADB = <CDB ( A )
DB = BD ( common side )
<ABD = <CBD ( A )
Therefore ,
∆ABD is congruent to ∆CBD
[ ASA criterion ]
••••
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