Question

In the given figures the side BC of angle abc has been produced on both sides on the left to d and on the right to E if angle abd = 106 and angle ace = 118 find the measure of each angle of the triagle abc is triangle and is produced to d and formed angle 106 and c is produeced to e and formed angle 118

Answer 1

∠ABD + ∠ABC = 180° (Angle on the same line) 

∠ABC = 180° - 106° = 74° 

∠ACB + ∠ACE = 180° 

∠ACB = 180° - 118° = 62° 

Now in ΔABC, 

∠ABC + ∠ACB + ∠BAC = 180° 

∠BAC = 180° - ∠ABC - ∠ACB 

= 180° - 74° - 62° 

= 44° 

Hence, ∠ABC = 74° 

∠ACB = 62° 

∠BAC = 44°

Answer 2

Answer:

Step-by-step explanation:

∠ABD + ∠ABC = 180° (Angle on the same line) 

∠ABC = 180° - 106° = 74° 

∠ACB + ∠ACE = 180° 

∠ACB = 180° - 118° = 62° 

Now in ΔABC, 

∠ABC + ∠ACB + ∠BAC = 180° 

∠BAC = 180° - ∠ABC - ∠ACB 

= 180° - 74° - 62° 

= 44° 

Hence, ∠ABC = 74° 

∠ACB = 62° 

∠BAC = 44°

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