In the given fugure a line segment PQ is drawn parallel to base BC of triangle ABC .If PQ:BC=1:3
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2
Answer:
4/1]
Step-by-step explanation:
ANSWER
Given,AP=1/3PB
So,AP/PB=1/3
In Δ APQ and Δ ABC,
As PQ || BC, corresponding angles are equal
∠APQ=∠ABC and ∠AQP=∠ACB
Hence, ΔAPQ ~ ΔABC by AA criterion for similarity
So,
Area of ΔABC/ Area of ΔAPQ=AB
2
/AP
2
=42/12=16:1
[AP/PB=1/3 so, AB/AP=4/1]
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