Question

In the given gifure, line l || line-segment AB. Find the values of x, y and z​

Answer 1

Answer:

here ABC is a triangle so sum of all angles are 180°(1st pic)

here angle y and angle z are complementary so sum of the angles is 90° 2nd pic

here angle x, y, z are supplementary angles third sum is 180° 3rd pic

l

Step-by-step explanation:

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Answer 2

Answer:

x + 1/ x = 2

Cubing both sides, we get -

x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8

= x^3 + 1/x^3 + 3 (x + 1/x) = 8

= x^3 + 1/x^3 + 3 × 2 = 8 (since, x + 1/ x = 2)

= x^3 + 1/x^3 = 8 - 6

or, x^3 + 1/x^3 = 2.

OR

Let p (x) = x + 1 / x = 2

Let p (x) = x + 1 / x = 2= x + 1 = 2x

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2

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