Question

In the given image if BCDE is a square, then what is the area of the biggest rectangle in
c
m
2
.

Answer 1

Answer:

cm2

Step-by-step explanation:

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Answer 2

Given:

CE = $3\sqrt{2}$ cm

AE = 5cm

To find:

Area of rectangle ACDF.

Formula to be used:

Area of rectangle is length x breadth.

Pythagoras theorem = $H^{2} =P^{2} +B^{2}$

Step-by-step explanation:

Step 1 of 3

In ΔEBC,

BC = BE

∠EBC=90°, so we can apply pythagoras theorem in this triangle.

$(3\sqrt{2} )^{2}=BE^{2} +BC^{2} \\ \\18=BE^{2} +BE^{2} \\\\18=2BE^{2}\\\\9=BE^{2} \\\\BE=3$

BE = BC = 3cm

Step 2 of 3

Similarly in ΔABE,

$5^{2} =BE^{2} +AB^{2} \\\\25=3^{2} +AB^{2} \\\\AB^{2} =25-9\\\\AB^{2} =16\\\\AB=4cm$

Step 3 of 3

Sides of rectangle,

BE = CD = 3cm

AC = AB + BC = 4 + 3 = 7cm

Area of rectangle ACDF =

$=AC *CD\\\\=7*3\\\\=21cm^{2}$

AREA OF RECTANGLE IS 21cm2.