in the given isosceles triangle the bisector of triangle y and triangle z meet at a point O if triangle x=70, find the measure of triangle yoz
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x+y+z=180° (angle sum of triangles)
70°+y+z=180°
y+z=110°
oyz+ozy=1/2×110° (as they were bisectors)
oyz+ozy=55° (1)
In triangle OYZ
yoz+oyz+ozy=180° (angle sum of triangles)
yoz+55°=180° (from 1)
yoz=125°
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