in the given , mention the congruence rule used in proving ACB= ACD
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In this theorem, We need two right angled triangle, (right angle) ∠90° are equal of two triangles, one hypotenuse is equal to the other triangle and one side of two triangles are equal
Step-by-step explanation:
AC=AD [ given]
angle CAB = angle BAD [ given ]
AB= AB [ common ]
Hence, the congruency rule used in proving ∆ACB ≈ ∆ ADB is SAS.
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