In the given network....find resistance between A and B
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In the given ciruit, the two 1 ohm resistors are connected in series.
So, they can be replaced with a resistor of equivalent resistance.
Req = 1 + 1 = 2 ohms (as they are in series)
So, both the 1 ohm resistors can be replaced by a 2 ohm resistor.
Now, the three two ohm resistors (2 in the figure, and 1 which we just added by replacing the 1 ohm resistors),
are in parallel
So, there equivalent resistance = (1/2 + 1/2 + 1/2)^-1
= (3/2)^-1
= 2/3 ohms.
Therefore, the equivalent resistance between A and B is 2/3 ohms
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