Question

In the given network of capacitors, the equivalent capacitance between points a and b is

Answer 1

ans = it depends on the situation that weathe it is in serise or it is in parallel.

if in serise.

then C = C1 + C2+ C3...

if in parallel then 1\C = 1\C1 + 1\C2 + 1\C3....

this formula can be used on any points a or b so the first task is to check weather the connection between the point is in serise or in parallel.

thankyou

Answer 2

Answer:

7.5 μF

Explanation:

Missing diagram in question attached.

Capacitor 4 μF and 6 μF are in parallel. So the corresponding equivalent capacitance will be 10 μF.

Capacitor 13 μF and 17 μF are in parallel. So the corresponding equivalent capacitance will be 30 μF.

Now, capacitor 10 μF and 30 μF are in series, so net capacitance will be

1/C(eff) = 1/10 + 1/30

Solving we get C(eff) = 7.5 μF