In the given neutralization reaction the equivalent
weight of base are respectively :-
H2PO4 + 2NaOH → Na2HPO4 + 2H2O
(1) 98, 40
(2) 98, 20
(3) 49, 20
(4) 49, 40
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Answer:
In the Given Reaction,
NaOH + H₃PO₄ ----------→ NaH₂PO₄ + H₂O
We know that for the Acids, the equivalent weight is equal to the ratio of the molar mass and number of the hydrogen ions of the acid accepted by the base.
∴ In the given reaction,
No. of hydrogen ions replaced by the Base of the Acid = 2
Molar mass of the Acid = 98 g/mole.
∴ Equivalent Weight = 98/2
= 49
Hence, the equivalent weight of the Acid is 49.
Explanation:
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