Question

In the given ,O is the centre of the circle and < ACB =30° ,find <AOB.

Answer 1

if CA and CB are taken as tangents, then as you have that\_ACB is 30°then by using angle sum property we get
30+90+90+X=360
X=360-210
X=150°
Therefore \_AOB=150°

Answer 2

where is the figures? how would i help u without a figure