Question

in the given parallelogram ABCD angle DAC 40 degree angle BAC 35 degree and Angle COD 65 degree find
angle abd
angle bdc
angle ACB
angle CBD

Answer 1

angle cod is 65 so so angle aob is 65( vertical opposite angle)
angle bac is35
so 35+65+dba=180 angle sum of triangle oab
so dba is 80
now second bdc is equal to dba so bdc is 80
dac is equal to acb so acb is 40
in triangle obc
angle acb +angle cob +angle dbc is 180
angle cob is found by linear pair i.e. 65+x is 180 so x is 115
115 +40+x is 180
x is 25 angle cbd is 25

Answer 2

$sorry \: for \: any \: mistakes$