Question

In the given parallelogram ABCD, ∆CAB =110` and∆DBC=30`. Find the measure of∆DCB and∆ACB​

Answer 1

Answer:

Opposite angles of parallelogram are equal.

∠DAB=∠BCD=75

o

and ∠DBC=60

o

∠BDC+∠DBC+∠BCD=180

o

∠BDC=180

o

−∠DBC−∠BCD=180

o

−75

o

−60

o

=45

o

Step-by-step explanation:

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