In the given parallelogram ABCD, ∆CAB =110` and∆DBC=30`. Find the measure of∆DCB and∆ACB
Answers
Answered by
2
Answer:
Opposite angles of parallelogram are equal.
∠DAB=∠BCD=75
o
and ∠DBC=60
o
∠BDC+∠DBC+∠BCD=180
o
∠BDC=180
o
−∠DBC−∠BCD=180
o
−75
o
−60
o
=45
o
Step-by-step explanation:
please please mark the brain lisit
Similar questions