Question

In the given parallelogram ABCD, ∠DAO = 35°, ∠BAO = 25° and ∠BOC = 60°, then find
(i) ∠ADO
(ii) ∠DBC
(iii) ∠ACB
(iv) ∠DBA

Answer 1

Answer:

given figure,

Quadrilateral ABCD is a parallelogram.

So, AD ∣∣ BC

∴ ∠DAC = ∠ACB --- ( Alternate angle)

∴ ∠ACB = 32

∘

∠AOB + ∠BOC = 180

∘

--- (straight angle)

⇒70

∘

+ ∠BOC = 180

∘

∴ ∠BOC = 110

∘

In △BOC,

∠OBC + ∠BOC + ∠OCB = 180

∘

⇒∠OBC + 110

∘

+ 32

∘

= 180

∘

⇒ ∠OBC = 38

∘

∴ ∠DBC = 38

∘

Answer 2

Step-by-step explanation:

given figure parallallogram abcd is parallel

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