in the given parallelogram ABCD, find the value of x and y. angleA= 3y , angleB= (2y-5) , angleC= (3x+3)
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Angle A=3y, B=2y-5, C=3x+3,
Angle D=180-3y (because A&D are supplementary)
Angle D+Angle B= 180°
180-3y+2y-5=180
-y-5=0
y= -5
Angle A+AngleC= 180°
3y+3x+3=180
x+y=59
substitute y in this equation: x-5=59
x=64
Therfore, x=64 & y= (-5)
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