In the given parallelogram ABCD, find the value of x and y A=3y , B=2y-5 C = 3x + 3
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Answer:
Since ABCD is a parallelogram, AB∥DC and AD∥BC
Now, AB∥DC and transversal BD intersects them.
∴∠ABD=∠BDC since alternate angles are equal.
⇒10x=60
∘
⇒x=
10
60
∘
=6
∘
And, AD∥BC and transversal BD intersects them.
∴∠DBC=∠ADB
⇒4y=28
∘
⇒y=
4
28
∘
=7
∘
Step-by-step explanation:
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