Question

in the given pentagon AB=BC=CD=DE=AE. the value of angle x is?​

Answer 1

Answer:

(2n-4)x90=(2x5-4) 90=540

x = 540/5=lo8 degree

OR

External angle sum=360

360/5=72 degree

internal angle x=l80-72=108 degree

Answer 2

The value of angle x is $54^{\circ}$

Explanation:

It is given that the pentagon AB=BC=CD=DE=AE

Let O be the centre of the pentagon.

Thus, the angle of O is given by

$\frac{360}{5} =72^{\circ$

Thus, the angle of O is $\angle O=72^{\circ$

To determine the value of angle x, let us add all the angles of the $\triangle AOE$

Thus, we have,

$\angle A+\angle E +\angle O=180^{\circ}$

       $x+x+72=180$

                    $2x=108$

                      $x= 54^{\circ}$

Thus, the value of angle x is $54^{\circ}$

Learn more:

(1) In a given pentagon ABCDE,AB=BC=CD=DE=AE THE VALUE OF X​

brainly.in/question/15368589

(2) In the given figure, ABCDE is a pentagon inscribed in a circle. If AB=BC=CD,angle BCD=110° and angleBAE=120°, find

1)angleABC,

2)angleCDE,

3)angle AED,

4)angleEAD

brainly.in/question/7885937