Question

in the given picture AB and CD are two intersecting chords of a circle. If <CAB =40 degree and <BCD = 80 degree, then <CBD= ?​

Answer 1

Answer:

< CAB = 40 =CDB (angle on same chord)

angle BCD = 80

Consider triangle BCD

angle c = 80, angle d,= 40, then 3rd angle b =

180 - (80 + 40) = 60 Ans

Answer 2

Answer:

80° + 40°+ x = 180°

120° + x = 180°

x= 180°-120°

x= 60°