Question

In the given polygon=BO=7x+4,OD=18​

Answer 1

Question :- .In the given polygon, BO = 7x + 4 and OD = 18. Find x ?

Solution :-

As from image we can see that, we have given

→ BC is parallel to AD .

→ AB is parallel to DC.

So, Polygon ABCD is a parallelogram.

Now, Diagonals BD and CA of parallelogram are intersecting at O.

As we know :-

• The diagonals of a parallelogram bisect each other.

Therefore,

• BO = OD
• AO = OC.

Than,

→ BO = OD

→ 7x + 4 = 18

→ 7x = 18 - 4

→ 7x = 14

Dividing both sides by 7,

→ x = 2. (Ans.)

Hence, value of x will be 2.

Answer 2

Given : BO = 7x + 4 and OD = 18  

To Find : x

Solution:

As shown , ABCD is a parallelogram

Diagonal AC & BD intersect at O

Diagonal of parallelogram bisect each other

=> BO = OD

BO = 7x + 4

OD = 18

Substituting these

7x + 4 = 18

Subtracting 4 from both sides

=> 7x + 4 - 4 = 18 - 4

=> 7x = 14

Dividing both sides by 7

=> x = 2

Learn more:

In quadrilateral abcd diagonal ac bisects diagonal bd at point o ...

brainly.in/question/13170843

prove that each diagonal of a Rhombus bisect the angle through ...

brainly.in/question/6014909

Complete the following: In a rhombus, the diagonals bisect each ...

brainly.in/question/7402304