Question

In the given quadrilateral ABCD, the side BD = 15 cm and the heights of the triangles ABD and BCD are 5 cm and 7 cm respectively. Find the area of the quadrilateral ABCD​

Answer 1

Answer:

=> The area of the quadrilateral ABCD is $90cm^2.$

Step-by-step explanation:

Given that:-

Diagonal = $BD = 15 cm$

Height = $h_1=5cm$ and $h_2=7cm$

To find:- The area of the quadrilateral ABCD,

The sum of the heights = $5+7$

                                       = 12 cm

As we know that,

The formula to be used for calculating the area  of quadrilateral,

$=\frac{1}{2}\times diagonal\times [sum of the heights]$

$=\frac{1}{2}\times 15\times 12$

By further calculation, we get

$=\frac{15\times 12}{2}$

=  $90cm^2.$

Hence, the area of the quadrilateral is $90cm^2.$